How To Find Discriminant Of Quadratic Equation
C Programme to Notice the Roots of a Quadratic Equation
In this case, y'all will learn to find the roots of a quadratic equation in C programming.
To sympathize this example, yous should take the noesis of the following C programming topics:
- C Programming Operators
- C if...else Argument
The standard form of a quadratic equation is:
ax2 + bx + c = 0, where a, b and c are real numbers and a != 0
The term bii; - 4ac
is known as the discriminant of a quadratic equation. It tells the nature of the roots.
- If the discriminant is greater than
0
, the roots are real and dissimilar. - If the discriminant is equal to
0
, the roots are real and equal. - If the discriminant is less than
0
, the roots are circuitous and different.
Plan to Find Roots of a Quadratic Equation
#include <math.h> #include <stdio.h> int master() { double a, b, c, discriminant, root1, root2, realPart, imagPart; printf("Enter coefficients a, b and c: "); scanf("%lf %lf %lf", &a, &b, &c); discriminant = b * b - 4 * a * c; // condition for existent and different roots if (discriminant > 0) { root1 = (-b + sqrt(discriminant)) / (two * a); root2 = (-b - sqrt(discriminant)) / (2 * a); printf("root1 = %.2lf and root2 = %.2lf", root1, root2); } // condition for existent and equal roots else if (discriminant == 0) { root1 = root2 = -b / (ii * a); printf("root1 = root2 = %.2lf;", root1); } // if roots are not real else { realPart = -b / (ii * a); imagPart = sqrt(-discriminant) / (two * a); printf("root1 = %.2lf+%.2lfi and root2 = %.2f-%.2fi", realPart, imagPart, realPart, imagPart); } render 0; }
Output
Enter coefficients a, b and c: 2.3 iv 5.6 root1 = -0.87+1.30i and root2 = -0.87-i.30i
In this program, the sqrt()
library role is used to find the foursquare root of a number. To larn more, visit: sqrt() role.
Source: https://www.programiz.com/c-programming/examples/quadratic-roots
Posted by: gillespieextesed.blogspot.com
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